Úprava formátování
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@ -10,13 +10,15 @@ Taylorův polynom tedy bude vypadat následovně.
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- $T_{n}(x) = a_{0} + a_{1}(x-x_{0}) + a_{2}(x-x_{0})^2 + \dots + a_{n}(x-x_{0})^n$
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- $T_{n}(x) = a_{0} + a_{1}(x-x_{0}) + a_{2}(x-x_{0})^2 + \dots + a_{n}(x-x_{0})^n$
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Platí tedy:
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Platí tedy:
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$$\begin{matrix}
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$$
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\begin{matrix}
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f(x_{0}) = T_{n}(x_{0}) = a_{0} \\
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f(x_{0}) = T_{n}(x_{0}) = a_{0} \\
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f'(x_{0}) = T_{n}'(x_{0}) = a_{1} \\
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f'(x_{0}) = T_{n}'(x_{0}) = a_{1} \\
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f''(x_{0}) = T_{n}''(x_{0}) = 2a_{2} \\
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f''(x_{0}) = T_{n}''(x_{0}) = 2a_{2} \\
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\vdots \\
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\vdots \\
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f^{(n)}(x_{0}) = T_{n}^{(n)}(x_{0}) = n! \, a_{n}
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f^{(n)}(x_{0}) = T_{n}^{(n)}(x_{0}) = n! \, a_{n}
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\end{matrix}$$
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\end{matrix}
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$$
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### Definice Taylorova polynomu
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### Definice Taylorova polynomu
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